# For the experiment of tossing a six sided die twice, what is the probability that the sum is at least 7?

Sep 29, 2017

$\frac{21}{36}$ or $\frac{7}{12}$

#### Explanation:

You want an outcome that is at least 7 (for two dices). The possible outcomes are: (1; 6), (2; 5), (2; 6), (3; 4), (3; 5), (3; 6), (4; 3), (4; 4), (4; 5), (4; 6), (5; 2), (5; 3), (5; 4), (5; 6), (6; 1), (6; 2), (6; 3), (6; 4), (6; 5), (6; 6).

Therefore, there are total 21 outcomes that satisfy this.

Total 36 outcomes are possible when you throw two dices.

Your probability is 21/36 = 7/12 = 58.33%