For the experiment of tossing a six sided die twice, what is the probability that the sum is 2, 3 or 12?

1 Answer
Mar 13, 2018

Answer:

#P(2,3,12) = 4/36 = 1/9#

Explanation:

If you toss the die twice, there are #6xx6 = 36# different outcomes.
Each of the #6# numbers for the first throw can be combined with each of the same six for the second throw.

Of those #36# outcomes, we only want:

a total of #2" "rarr# this can only come from #1+1=2#
a total of #3" "rarr# this can come from #1+2=3 or 2+1=3#
a total of #12" "rarr# this can only come from #6+6=12#

So, of the total of #36# possible outcomes, there are only #4# that we want.

#P(2,3,12) = 4/36 = 1/9#