# For the experiment of tossing a six sided die twice, what is the probability that the sum is odd and no more than 7?

Jan 12, 2018

See a solution process below:

#### Explanation:

From this chart you can see there are a possible of $36$ outcomes from tossing the die twice:

Out of these there are $12$ outcomes which are odd and not greater than $7$:

Therefore the Probability is:

$\frac{12}{36} = \frac{1}{3}$ or $1 \text{ in } 3$ or 33.3%