For the reaction #2MnO_2 + 4KOH + O_2 + Cl_2 -> 2KMnO_4 + 2KCl + 2H_2O#, there are 100.0 g of each reactant available. Which reactant is the limiting reagent?

1 Answer
Jun 20, 2016

Answer:

Surely it is the base?

Explanation:

Referring directly to your balanced chemical equation, there are
#(100.0*g)/(86.94*g*mol^-1)MnO_2=1.15*mol#

#(100.0*g)/(56.11*g*mol^-1)KOH=1.78*mol#

#(100.0*g)/(32.00*g*mol^-1)O_2=3.13*mol#
And,
#(100.0*g)/(70.9*g*mol^-1)Cl_2=1.41*mol#

I think the identity of the limiting reagent is fairly clear.