# For what values of x, if any, does #f(x) = 1/((x+12)(x-1)) # have vertical asymptotes?

##### 1 Answer

Jun 11, 2016

#### Answer:

vertical asymptotes x = -12 , x = 1

#### Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s set the denominator equal to zero.

solve: (x+12)(x-1) = 0 → x = -12 , x = 1 are the asymptotes.

graph{1/((x+12)(x-1) [-20, 20, -10, 10]}