For what values of x, if any, does #f(x) = 1/((x+12)(x-3)) # have vertical asymptotes?
In x=-12 and x=3
If we replace x by -12 or 3, the denominator will be zero, which means:
But what kind of infinity you have when x has those values?
If you use
By the other hand if you use
If by on side you have