Question

For what values of x, if any, does `f(x) = 1/((x+12)(x-6))` have vertical asymptotes?

Answer 1

`x=-12` and `x=6`

Explanation:

A vertical asymptote occurs when the denominator equals 0.

So, we have `(x+12)(x-6)=0`

Either `x+12=0` or `x-6=0`

By rearranging we get:
`x=-12` and `x=6`