# For what values of x, if any, does f(x) = 1/((x+12)(x-6))  have vertical asymptotes?

Apr 30, 2018

$x = - 12$ and $x = 6$

#### Explanation:

A vertical asymptote occurs when the denominator equals 0.

So, we have $\left(x + 12\right) \left(x - 6\right) = 0$

Either $x + 12 = 0$ or $x - 6 = 0$

By rearranging we get:
$x = - 12$ and $x = 6$