Question

For what values of y is the function undefined: `y=(2x-5)/(x+3)`?

Answer 1

See the explanation

Explanation:

If a function in `x` is undefined then `y` can not take on a value.

If `y` can take on a value then the function is defined.

`y=(2x-5)/(x+3)` is undefined at `x=-3`

If this were to be the case we would have

`y=(-6-5)/0` you are 'not allowed' to have 0 as a denominator. Hence 'undefined'