For which value of #m# does the graph of #y=18x^2+mx+2# have exactly one #x#-intercept?

1 Answer
Apr 18, 2016

We will have exactly one intercept for #m=+-12#

Explanation:

As #y=18x^2+mx+2# will have two intercepts on #x#-axis given by

#18x^2+mx+2=0#

If the discriminant is zero the intercepts will coincide.

As the discriminant is #m^2-4xx2xx18=m^2-144#,

we will have exactly one intercept if #m^2-144=0# or #m=+-12#

i.e. for #y=18x^2-12x+2# and #y=18x^2+12x+2#

graph{18x^2-12x+2 [-3, 3, -2, 5]}

graph{18x^2+12x+2 [-5, 5, -2, 5]}