# For y = x^2 - 2, if the x-values are -3, -2, 0, 1, 2 what are the y values?

Mar 13, 2018

${y}_{- 3} = 7$
${y}_{- 2} = 2$
${y}_{0} = - 2$
${y}_{1} = - 1$
${y}_{2} = 2$

#### Explanation:

$y = {x}^{2} - 2$

${y}_{\left(- 3\right)} = {\left(- 3\right)}^{2} - 2 = 9 - 2 = 7$
${y}_{\left(- 3\right)} = 7$

${y}_{\left(- 2\right)} = 2$
${y}_{0} = - 2$
${y}_{1} = - 1$
${y}_{2} = 2$

Mar 13, 2018

See below...

#### Explanation:

By plugging in the corresponding $x$ values, we can get the $y$ value, as the answer is equal to the $y$ value.

When:

$x = - 3 , - 2 , 0 , 1 , 2$ Shown by the equation, $y = {x}^{2} - 2$. Just plug in the corresponding $x$ value, to obtain the $y$ value.

$\therefore$ when $x = - 3$ $y = {\left(- 3\right)}^{2} - 2 = 9 - 2 = 7$ remembering a $- \times - = +$

when $x = - 2$

$y = {\left(- 2\right)}^{2} - 2 = 4 - 2 = 2$

when $x = 0$

$y = {0}^{3} - 2 = 0 - 2 = - 2$

when $x = 1$

$y = {1}^{2} - 2 = 1 - 2 = - 1$

when $x = 2$

$y = {2}^{2} - 2 = 4 - 2 = 2$