For #y = x^2 - 2#, if the x-values are -3, -2, 0, 1, 2 what are the y values?

2 Answers
Mar 13, 2018

Answer:

#y_(-3)=7#
#y_(-2)=2#
#y_(0)=-2#
#y_(1)=-1#
#y_(2)=2#

Explanation:

#y = x^2 - 2#

#y_((-3)) = (-3)^2-2 = 9-2 = 7#
#y_((-3))=7#

#y_((-2))=2#
#y_(0)=-2#
#y_(1)=-1#
#y_(2)=2#

Mar 13, 2018

Answer:

See below...

Explanation:

By plugging in the corresponding #x# values, we can get the #y# value, as the answer is equal to the #y# value.

When:

#x=-3,-2,0,1,2# Shown by the equation, #y=x^2-2#. Just plug in the corresponding #x# value, to obtain the #y# value.

#therefore# when #x=-3# #y=(-3)^2-2=9-2=7# remembering a #- xx - =+#

when #x=-2#

#y=(-2)^2-2=4-2=2#

when #x=0#

#y=0^3-2=0-2=-2#

when #x=1#

#y=1^2-2=1-2=-1#

when #x=2#

#y=2^2-2=4-2=2#