Gas samples A, B, C are contained at STP. Partial pressure of sample A is 38.0 kPa and sample B is 19.0 kPa. What is the partial pressure of sample C?

2 Answers
Dec 2, 2015

Answer:

#=>P_C=44.3kPa#

Explanation:

If the mixture of gases A, B and C is contained at STP, this means that the total pressure is 1 atm.

Note that #1atm=101.325kPa#

According to Dalton's law, the total pressure of a mixture is equal to the sum of the partial pressures of the gases in the mixture:

#P_("total")=P_A+P_B+P_C#

#=>P_C=P_("total")-P_A-P_B#

#=>P_C=101.325kPa-38.0kPa-19.0kPa=44.3kPa#

Dec 2, 2015

Answer:

Pressures are additive. The pressure exerted by C is approx. 44 kPa.

Explanation:

Dalton's law of partial pressures states that in a gaseous mixture the partial pressure exerted by each component is the same pressure it would exert if it ALONE occupied the container; the total pressure is the sum of the partial pressures. We know that the total pressure is atmospheric, 101.3 kPa. Since the partial pressures, #P_A#, and #P_B# are known, #P_C# is simply the difference between these pressures and the total pressure:

#P_C = 101.3 - P_A - P_B = ?? kPa#