# Given a solution with a pH of 2.8, what is the H^+ of the solution?

${H}^{+}$ $=$ ${10}^{- 2.8} \cdot m o l \cdot {L}^{-} 1$
$p H = - {\log}_{10} \left[{H}^{+}\right]$
Thus $\left[{H}^{+}\right]$ $=$ ${10}^{- p H} \cdot m o l \cdot {L}^{-} 1$