# Given #((e^h)-1)/(h)# how do you find the limit as h approaches 0?

##### 2 Answers

#### Explanation:

We use series expansion of

Hence

and

Hence

See below

#### Explanation:

If this is part of the derivation of the fact that

I may be wrong but I think we should still be allowed to use Bernoulli's compounding formula

or, here

So