Question

Given f(x)= -2sin x, g(x)= sin 2x, how do you graph h(x)= (f+g)(x)?

Answer 1

I can show how it looks like..

Explanation:

the graph of `f(x)=-2sin x` alone
graph{((y+2*sin x))=0[-6,6,-3,3]}

the graph of `g(x)=sin 2x`
graph{((y-2sin xcos x))=0[-6,6,-3,3]}

the graph of `f(x)` and `g(x)` together in one coordinate system
graph{((y+2sin x)(y-2sin x*cos x))=0[-6,6,-3,3]}

the graph of `h(x)=(f+g)(x)=-2sin x+sin 2x`
graph{((y+2sin x)+(y-2sin x*cos x))=0[-6,6,-3,3]}