Question

Given `f(x)=3x-1, g(x)=x^2-7, h(x)=x^4`, how do you find `f(g(h(x))`?

Answer 1

`3x^8-22`

Explanation:

To evaluate `f(g(h(x))` first evaluate `g(h(x))` That is the 'inner' function.

To evaluate g(h(x)) substitute `x=x^4` into g(x))

`rArrg(h(x))=(x^4)^2-7=x^8-7`

Now to evaluate f(g(h(x)) substitute `x=x^8-7` into f(x)

`rArrf(g(h(x))=f(x^8-7)-1=3(x^8-7)-1`

`=3x^8-21-1=3x^8-22`