Given H = x^2 + 8, what is H^-1?

1 Answer
Oct 14, 2016

The notation H^-1 means the inverse function. The equation of the inverse function can be found by switching the x and y values inside the function.

y = x^2 + 8

x = y^2 + 8

x - 8 = y^2

y = +-sqrt(x - 8)

Hence, H^-1(x) = +-sqrt(x- 8).

Hopefully this helps!