Question

Given h(x) = f (g(x)). If g(2) = −3, g′ (2) = 4 and f′ (−3) = 7, find h′ (2).?

Answer 1

`h'(2) = 28`

Explanation:

Recall that by the chain rule

`h'(x) = f'(g(x)) * g'(x)`

Therefore

`h'(2) = f'(g(2)) * g'(2) = f'(-3) * 4 = 7 * 4 = 28`

Hopefully this helps!