Question

Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 400,000?

Answer 1

`log400,000=5.6021`

Explanation:

`log400,000`

= `log(4xx100,000)`

= `log(4xx10^5)`

As `log(mxxn)=logm+logn` and `loga^n=nloga`,

we can write te above as

`log4+5log10`

but `log10=1`

Hence `log400,000=log4+5xx1=0.6021+5=5.6021`

Note : Value of `log9` and `log12` is not needed.