Given log4=0.6021, log9=0.9542, and log12=1.-792, how do you find log 400,000?

1 Answer
Jan 21, 2017

Answer:

#log400,000=5.6021#

Explanation:

#log400,000#

= #log(4xx100,000)#

= #log(4xx10^5)#

As #log(mxxn)=logm+logn# and #loga^n=nloga#,

we can write te above as

#log4+5log10#

but #log10=1#

Hence #log400,000=log4+5xx1=0.6021+5=5.6021#

Note : Value of #log9# and #log12# is not needed.