Question

Given P(A) = 0.4, P(B) = 0.35, and P(A intersect B) = 0.14, what is the probability that neither A nor B takes place?

Answer 1

Probability that neither A nor B takes place is `0.39`.

Explanation:

As `P(A)=0.4, P(B)=0.35`, and `P(AnnB)=0.14`,

`P(AuuB)=P(A)+P(B)-P(AnnB)`

= `0.4+0.35-0.14=0.61`

As `P(AuuB)=0.61`,

the probability that neither A nor B takes place is `1-0.61=0.39`