Given ${sin 30}^{\circ} = \frac{1}{2}$ $sin30^circ=1/2$ and ${tan 30}^{\circ} = \frac{\sqrt{3}}{3}$ $tan30^circ=sqrt3/3$ , how do you find ${csc 30}^{\circ}$ $csc30^circ$ ?

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Answer 1 · 2017-02-16T01:51:26

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$sin (30) = \frac{1}{2}$ $sin (30) = 1/2$
$csc (30) = \frac{1}{sin} = 2$ $csc (30) = 1/(sin) = 2$ .

Given sin30∘=12sin30^circ=1/2 and tan30∘=√33tan30^circ=sqrt3/3, how do you find csc30∘csc30^circ?