Question

Given `tanx=5/12, secx=13/12` to find the remaining trigonometric function?

Answer 1

`sec x = 1/(cos x) = 13/12` --> `cos x = 12/13`
`tan x = 5/12`
`sin x = tan x.cos x = (5/12)(12/13) = 5/13`
`cot x = 1/(tan x) = 12/5`
`csc x = 1/(sin x) = 13/5`