Given that #f(x)=sqrtx# and #g(x)=4x+2#, how do you find #(fog)(x)#?

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Answer 1 · 2017-01-18T07:54:37

#f(x)=sqrt(x)# and #g(x)=4x+2# #=># #(f@g)(x)=sqrt(4x+2)#

Another way to write this is

#(f@g)(x)=f(g(x))#

This shows that when you are taking #(f@g)(x)# you are replacing the #x# in #f(x)# with the function #g(x)#.

So, if

#f(x)=sqrt(x)#

and

#g(x)=4x+2#

then

#(f@g)(x)=f(g(x))=sqrt(g(x))=sqrt(4x+2)#