Given that #f(x)=sqrtx# and #g(x)=4x+2#, how do you find #(gof)(x)#?
1 Answer
Aug 27, 2017
Explanation:
#"substitute "x=sqrtx" into "g(x)#
#(g@f)(x)=g(f(x))#
#color(white)((g@f)(x))=g(sqrtx)#
#color(white)((g@f)(x))=4sqrtx+2#
