# Given the eqn 2y^2 - 2xy - 4y + x^2 = 0 , how to get the x coordinates of each point at which the curve has a horizontal tangent?

##### 1 Answer

Feb 18, 2018

Use Calculus

#### Explanation:

Implicitly differentiate both sides of the equation, rearrange to get

Horizontal tangent: gradient =0

So horizontal tangents occur when y=x