Given the equation: CaC2(s) +2H2O(l) --> C2H2(g) + Ca(OH)2(s), 155 g CaC2 (s) reacts with 125 g H2O, what is the limiting reactant?

1 Answer
Nov 29, 2015

Answer:

#Ca{C-=C}(s) + 2H_2O(l) rarr HC-=CH(g)uarr + Ca(OH)_2(aq)#

Calcium carbide is clearly the reagent in deficiency.

Explanation:

Moles of water #=# #(125*g)/(18*g*mol^(-1))# #=# #6.94*mol#

Moles of carbide #=# #(155*g)/(64.1*g*mol^(-1))# #=# #2.4*mol#

So how much acetylene am I going to get?