# Given the equation: CaC2(s) +2H2O(l) --> C2H2(g) + Ca(OH)2(s), 155 g CaC2 (s) reacts with 125 g H2O, what is the limiting reactant?

Nov 29, 2015

$C a \left\{C \equiv C\right\} \left(s\right) + 2 {H}_{2} O \left(l\right) \rightarrow H C \equiv C H \left(g\right) \uparrow + C a {\left(O H\right)}_{2} \left(a q\right)$

Calcium carbide is clearly the reagent in deficiency.

#### Explanation:

Moles of water $=$ $\frac{125 \cdot g}{18 \cdot g \cdot m o {l}^{- 1}}$ $=$ $6.94 \cdot m o l$

Moles of carbide $=$ $\frac{155 \cdot g}{64.1 \cdot g \cdot m o {l}^{- 1}}$ $=$ $2.4 \cdot m o l$

So how much acetylene am I going to get?