Given the equation of a circle: #(x-3)^2+(y+2)^2=25#, how do you find the center and the radius?

1 Answer
Dec 9, 2015

Answer:

center: #(3,-2)#
radius: #5#

Explanation:

The general form for the equation of a circle with center #(color(red)(a),color(blue)(b))# and radius #color(green)(r)# is
#color(white)("XXX")(x-color(red)(a))^2+(y-color(blue)(b))^2=color(green)(r)^2#

#(x-3)^2+(y+2)^2=25#
can be easily transformed into the general form as:
#color(white)("XXX")(x-color(red)(3))^2+(y-color(blue)((-2)))^2=color(green)(5)^2#