Given the Following: heat of fusion of ice = 80.0 cal/g; specific heat of ice = 0.480 cal/g; and specific heat of water = 1.00 cal/g. Calculate the amount of heat required to melt 30.0 g of ice at 0 degrees celsius?

1 Answer
anor277
Jul 4, 2017

We wish to assess the enthalpy change for the physical reaction......

Explanation:

H_2O(s) +DeltararrH_2O(l).......

Note that BOTH the ice and water have a specified temperature of 0 ""^@C, and thus we assess the heat involved in the phase change, and thus we only need the "latent heat of fusion of ice", 80.0*cal*g^-1.

And for the given quantity, this 80*cal*g^-1xx30*g=2400*cal; whatever a "calorie" is...........

By the same token, we would report the enthalpy change of the reverse reaction......

H_2O(l) +DeltararrH_2O(s), DeltaH^@=-2400*cal. Do you agree?

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