Given the following, what is the molarity of the acetic acid? If the density of the vinegar is 1.006 g/cm what is the mass percent of acetic acid in the vinegar?
A 10.00-mL sample of vinegar,an aqueous solution of acetic acid (#HC_2H_3O_2# ), is titrated with 0.5062 M #NaOH# and 16.58 mL is required to reach the equivalence point.
A 10.00-mL sample of vinegar,an aqueous solution of acetic acid (
1 Answer
The molarity and mass percent of the vinegar are 0.8393 mol/L and 5.010 %.
Explanation:
Step 1. Use the titration data to calculate the molarity.
The balanced equation is
#color(blue)(bar(ul(|color(white)(a/a)"Molarity" = "moles"/"litres"color(white)(a/a)|)))" "#
∴
Step 2. Calculate the mass percent.
#color(blue)(bar(ul(|color(white)(a/a)"Mass percent" = "mass of sample"/"mass of solution" × 100 %color(white)(a/a)|)))" "#
We have 8.393 mmol of acetic acid in 10.00 mL of vinegar.