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Given the function f defined by f(x) =(2x-2)/(x^2+x-2) for what values of x is f(x) discontinuous?

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Jim H Share
May 1, 2018

Answer:

#f# is discontinuous at #-2# and at #1#

Explanation:

A rational function (like this one) is discontinuous where it is undefined.
That happens where the denominator is #0#

#x^2+x-2=0#

#(x+2)(x-1)=0#

#x=-2# OR #x=1#

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