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# Given the function f defined by f(x) =(2x-2)/(x^2+x-2) for what values of x is f(x) discontinuous?

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#### Explanation

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#### Explanation:

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Jim H Share
May 1, 2018

$f$ is discontinuous at $- 2$ and at $1$

#### Explanation:

A rational function (like this one) is discontinuous where it is undefined.
That happens where the denominator is $0$

${x}^{2} + x - 2 = 0$

$\left(x + 2\right) \left(x - 1\right) = 0$

$x = - 2$ OR $x = 1$

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