Question

Given the functions `f(x)=x-7` , `g(x)=x^2` and `h(x)=(x-7)^2` how do you find (f*g)(x)?

Answer 1

`(f*g)(x)=x^3-7x^2`

Explanation:

`f(x)=x-7` , `g(x)=x^2` , `h(x)=(x-7)^2`

Finding: `(f*g)(x)`:

`(f*g)(x)=f(x)*g(x)`

`=(x-7)*x^2`

`=x*x^2-7*x^2`

`=x^3-7x^2`