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Given the functions $f (x) = x - 7$ $f(x)=x-7$ , $g (x) = x^{2}$ $g(x)=x^2$ and $h (x) = {(x - 7)}^{2}$ $h(x)=(x-7)^2$ how do you find h(g(x))?

1 Answer

Oct 20, 2015

$h (g (x)) = x^{4} - 14 x^{2} + 49$ $h(g(x)) = x^4-14x^2+49$

Explanation:

If $h (x) = {(x - 7)}^{2}$ $h(x) = (x-7)^2$
then
$h (g (x)) = {(g (x) - 7)}^{2}$ $h(g(x)) = (g(x)-7)^2$

and if $g (x) = x^{2}$ $g(x)=x^2$
then
$h (g (x)) = {(x^{2} - 7)}^{2}$ $h(g(x)) = (x^2-7)^2$

$XXXX = x^{4} - 14 x^{2} + 49$ $color(white)("XXXX")=x^4-14x^2+49$

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