# Given the point P(8/17, 15/17), how do you find sintheta and costheta?

Oct 31, 2016

$\sin t = \frac{15}{17}$
$\cos t = \frac{8}{17}$

#### Explanation:

Point P (8/17, 15/17) is located on Quadrant I of the unit circle with diameter R = 1.
Right triangle formula:
${R}^{2} = \frac{{8}^{2} + {15}^{2}}{289} = \frac{289}{289} = 1$ --> R = 1
There for, by definition of the trig functions sin x and cos x -->
$\sin t = \frac{15}{17}$
$\cos t = \frac{8}{17}$