# Given the point P(sqrt2/2, sqrt2/2), how do you find sintheta and costheta?

Jan 16, 2017

Cal P (sqrt2/2, sqrt2/2) the terminal point of the arc t.
The radius of the circle will be:
$O P = \sqrt{\frac{2}{4} + \frac{2}{4}} = \sqrt{\frac{4}{4}} = \frac{2}{2} = 1$
That is the radius of the unit circle. There for:
$\sin t = \left(\frac{\sqrt{3}}{2}\right)$
$\cos t = \frac{\sqrt{3}}{2}$
tan t = 1
cot = 1
$\sec t = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3}$
$\csc t = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3}$