Question

Given `theta = (19pi) / 6` how do you find `tantheta`?

Answer 1

`tan((19pi)/6) = 1/sqrt(3)`

Explanation:

`theta =(19 pi)/6 = 2pi + (pi+pi/6)`

So `theta` has a reference angle of `pi/6` in quadrant 3.

`tan(theta)` is positive in quadrant 3 and
`pi/6` is a standard angle with `tan(pi/6) = 1/sqrt(3)`