H_2SO_4 is the formula for what common polyprotic acid?

Jun 9, 2016

$\text{Sulfuric acid}$

Explanation:

Both sulfuric acid, and its conjugate base, $H S {O}_{4}^{-}$ are strong acids in water for which the equilibrium lies strongly on the right:

${H}_{2} S {O}_{4} \left(a q\right) + 2 {H}_{2} O \left(l\right) r i g h t \le f t h a r p \infty n s 2 {H}_{3} {O}^{+} + S {O}_{4}^{2 -}$. Pure sulfuric acid is a water like solvent that undergoes the equilibium:

$2 {H}_{2} S {O}_{4} \left(l\right) r i g h t \le f t h a r p \infty n s {H}_{3} S {O}_{4}^{+} + H S {O}_{4}^{-}$.

In this solvent regime (which would require specialized equipment and water free conditions to study), the acid is ${H}_{3} S {O}_{4}^{+}$, and the base, bisulfate ion, $H S {O}_{4}^{-}$.