Question

Helium gas is heated at constant pressure by`10^0 C`. The percentage of heat energy supplied which is used in increasing the internal energy of the gas is? (A) 60% (B) 71% (C) 75% (D) 100%

Answer 1

60 %

Explanation:

For isobaric process ,total heat energy is expressed as `n Cp dt`
And internal energy as `n Cv dt`
So, internal energy is`(n Cv dt)/(n Cp dt)` times of total energy supplied i.e `(Cv)/(Cp)`
Helium being a monoatomic gas its gamma value is `5/3` = `(Cp)/(Cv)`
Hence, the percentage is `(3/5)*100`or 60 %