# Hello friends, please, I need to know how to get the answer out of this exponential equation? thank you

Nov 4, 2016

I'll help you with question $1$.

Write in the same base.

${3}^{x - 1} = {\left({3}^{-} 1\right)}^{- 2 x - 1}$

${3}^{x - 1} = {3}^{2 x + 1}$

We can now solve as a linear equation, since the bases are equivalent.

$x - 1 = 2 x + 1$

$x = - 2$

Hopefully this helps!