Question

Hoe do you differentiate `f(x)=ln(e^(4x)/x)`?

Answer 1

`4-1/x`

Explanation:

Use log laws to expand
`f (x)=ln [(e^(4x))/x]`
`=ln ((e^(4x))-ln (x)`
`=4x-lnx`
Differentiating with respect to x.
`d/dx (f (x))=d/dx [(4x)-ln (x)]`
`=d/dx(4x)-d/dx (ln (x))`
`:.=4-1/x`