Question

How can this be solved?

`cos4x(cosx-1) = 0`

Can you also let me know what the +1 equals to in a situation?

For example, "cosx + 1", along with other functions that have a +1

Answer 1

To answer your other question:
So:
`x=0+2pin`
`x= pi/8+pi/2n`
`x= (3pi)/8+pi/2n`

Explanation:

`cos4x(cosx-1)=0`

`cosx=1`
`cos4x=0`

`x=0+2pin`
`4x= pi/2+2pin`
`4x= (3pi)/2+2pin`

So:
`x=0+2pin`
`x= pi/8+pi/2n`
`x= (3pi)/8+pi/2n`

Here's a graph:
graph{cos(4x)(cosx-1) [-10, 10, -5, 5]}

To answer your other question:

"For example, "cosx + 1", along with other functions that have a +1":

The `+1` symbolizes a vertical shift, the function `cosx` has been shifted up 1 unit

For example:

graph{cosx [-10, 10, -5, 5]}
Graph of Cosx
graph{cosx+1 [-10, 10, -5, 5]}
Graph of Cosx+1