How can you evaluate #(k-4h+2)/(2k)+(4k+3h-1)/(7k)#?
1 Answer
Aug 14, 2015
Explanation:
Notice that you need to add two fractions, one that has the denominator equal to
Right from the start, the first thing that you need to do is find the common denominator, which in your case is
To get both fractions to have the same denominator, multiply the first one by
#(7 * (k - 4h + 2))/(7 * 2k) + (2 * (4k + 3h - 1))/(2 * 7k)#
#(7k - 28h + 14)/(14k) + (8k + 6h - 2)/(14k)#
Now simply add the two numerators to get
#(7k - 28h + 14 + 8k + 6h - 2)/(14k)#
To simplify this fraction, combine like terms
#(7k + 8k - 28h + 6h + 14 - 2)/(14k)#
#color(green)((15k - 22h + 12)/(14k))#