How can you find 2 zeros of this equation #y^2-5y+6=0#?

1 Answer
Aug 1, 2018

#y=3" or "y=2#

Explanation:

#"factor the quadratic and solve for y"#

#"the factors of "+6" which sum to "-5" #

#"are "-2" and "-3#

#(y-2)(y-3)=0#

#"equate each factor to zero and solve for y"#

#y-2=0rArry=2#

#y=3=0rArry=3#
graph{x^2-5x+6 [-10, 10, -5, 5]}