How did DeBroglie's hypothesis account for the fact that the energy in a hydrogen atom is quantised?

1 Answer
Jan 16, 2015

Bohr assumed that electrons move in an orbit around the central nucleus and only certain orbits are allowed.

The electron can be considered as a standing wave. This means that only an integral number of wavelengths can fit into a circular orbit. So we can write:

nlambda =2pirnλ=2πr

nn is an integer

lambdaλ = wavelength of electron

rr = radius of orbit.

The wavelength of the electron is given by the de Broglie expression:

lambda =(h)/(mv)λ=hmv

Where:

hh = the Planck Constant

mm = mass of electron

vv = velocity of electron

Substituting for lambdaλ into the 1st equation we get:

(nh)/(mv)=2pirnhmv=2πr

The angular momentum of the electron = mvrmvr so rearranging we get:

mvr = (nh)/(2pi)mvr=nh2π

This is an important result in that it tells us that the angular momentum of the electron can only take integral values of (h)/(2pi)h2π I.e it is quantised.