# How do I evaluate #int(1-sinx)/cosx dx#?

##### 1 Answer

Jan 31, 2015

Well, this one is a little bit tricky...

I started with the idea that the result must be a logarithm...

So I did a little manipulation to get to a friendlier version of your function by multiplying and dividing by:

Which derived gives (1) or your original function!!!!!