Question

How do I evaluate lim x approaches 0 of Sin8x/x?

Answer 1

`lim_(x→0) (sin8x)/x=8`

Explanation:

`lim_(x→0) (sin8x)/x=lim_(x→0) (8sin8x)/(8x)=8lim_(x→0)(sin8x)/(8x)`

We now use the well known limit `lim_(vartheta→0) sinvartheta/vartheta=1`

to get a final answer of `8`.