How do I evaluate lim x approaches 0 of Sin8x/x?

1 Answer
Monzur R.
Feb 11, 2018

#lim_(x→0) (sin8x)/x=8#

Explanation:

#lim_(x→0) (sin8x)/x=lim_(x→0) (8sin8x)/(8x)=8lim_(x→0)(sin8x)/(8x)#

We now use the well known limit #lim_(vartheta→0) sinvartheta/vartheta=1#

to get a final answer of #8#.

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