How do I Evaluate the expression #x^2+6x−6# at #x=−2+i#. Write your answer in standard #a+bi# form?

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Answer 1 · 2018-05-22T15:08:14

#-15+2i#

As #x=-2+i#,

#x^2+6x-6#

= #(-2+i)^2+6(-2+i)-6#

= #(-2)^2 + 2*(-2)*i + i^2+ 6*(-2) + 6i -6#

= #4-4i-1-12+6i-6#

= #(4-1-12-6)-4i+6i#

= #-15+2i#