# How do I find all real and complex zeros of x^2+1?

Sep 25, 2014

You find the zeros by setting the expression equal to zero.

${x}^{2} + 1 = 0$

Then solve for $x$

${x}^{2} = - 1$

$\sqrt{{x}^{2}} = \pm \sqrt{- 1}$

$x = \pm i$

This expression has 2 imaginary roots $+ i$ and $- i$.