# How do I find the antiderivative for (1/sqrt(x) + 2/x^3) dx?

$\int \frac{1}{\sqrt{x}} \mathrm{dx} + \int \frac{2}{x} ^ 3 \mathrm{dx} =$
$= \int {x}^{- \frac{1}{2}} \mathrm{dx} + 2 \int {x}^{-} 3 \mathrm{dx} =$
$\int {x}^{n} \mathrm{dx} = {x}^{n + 1} / \left(n + 1\right) + c$