Question

How do I find the derivative of `y=(ln(3x))/(3x`?

Answer 1

You can use the Qotient Rule:
Given: `y=f(x)/g(x)`
Then: `y'=(f'(x)g(x)-f(x)g'(x))/(g(x))^2`

In your case:
`y'=(3/(3x)*3x-ln(3x)*3)/(3x)^2=`
`=(3-3ln(3x))/(9x^2)=(1-ln(3x))/(3x^2)`