Question

How do I find the value of cos pi/12?

Answer 1

It is `cos(pi/12)=1/4*(sqrt2+sqrt6)`

Explanation:

It is

`cos(pi/12)=cos(pi/3-pi/4)=cos(pi/4)cos(pi/3)+sin(pi/4)sin(pi/3)=sqrt2/2*1/2+sqrt2/2*sqrt3/2=1/4*(sqrt2+sqrt2*sqrt3)=1/4(sqrt2+sqrt6)`