Question

How do I find the value of sec 11pi / 6?

Answer 1

Find `sec ((11pi)/6)`

Ans: `(2sqrt3)/3`

Explanation:

`sec ((11pi)/6) = 1/cos ((11pi)/6)`. Find `cos ((11pi)/6)`
On the trig unit circle,
`cos ((11pi)/6) = cos (-pi/6 + 2pi) = cos (-pi/6) = cos (pi/6) = sqrt3/2`
Finally, `sec ((11pi)/6) = 2/sqrt3 = (2sqrt3)/3`